Lathan Subnetting

1. Perhatikan Gambar berikut :

Ketiga bangunan (building) tersebut memiliki blok alamat IP 10.131.234.0 /24. Tentukan jumlah subnet yang terdapat pada jaringan di atas! Lakukanlah subnetting sehingga diperoleh pengalamatan IP yang efisien (tentukan alamat network, alamat broadcast , serta host range masing-masing subnet)!

Jawab :

10.131.234.0 = 00001010.10000011.11101010.00000000

Bangunan B :

2⁷ = 128

Prefix : 32 – 7 = 25

Net Address : 00001010.10000011.11101010.0000000 = 10.131.234.0 /25

Host Range : 10.131.234.1 – 10.131.234.126

Broadcast : 00001010.10000011.11101010.01111111 = 10.131.234.127 /25

Bangunan C :

2⁶ = 64

Prefix : 32 – 6 = 26

Net Address : 00001010.10000011.11101010.10000000 = 10.131.234.128

Host Range : 10.131.234.128 – 10.131.234.190

Broadcast : 00001010.10000011.11101010.10111111 = 10.131.234.191

Bangunan A

2⁵ = 32

Prefix : 32 – 5 = 27

Net Address : 00001010.10000011.11101010.11000000 = 10.131.234.192 / 27

Hostrange : 10.131.234.193 – 10.131.234.222

Broadcast : : 00001010.10000011.11101010.11011111 = 10.131.234.223 /27

2. Tentukan network address, broadcast address , dan host range-nya!

· 172.16.155.32 netmask 255.255.240.0

· 172.171.4.193 netmask 255.224.0.0

· 192.168.36.116 /28

· 192.168.42.159 /27

Jawab :

a. 10101100.00010000.10011011.00100000 / 28

Net Address : 172.16.144.00

Host Range : 172.16.155.33 – 172.16.170.255

Broadcast : 172.16.170.255

b. 172.171.4.193/11

10101100.10101011.xxxxxxxx.xxxxxxxx

NetAdress : 172.160.0.0

Host Range : 172.160.0.1 – 172.191.255.254

Broadcast : 172.191.255.255

c. 192.168.36.116/28

xxxxxxxx.xxxxxxxx.xxxxxxxx.01110100

Net Address : 192.168.36.112

Host range : 192.168.36.113 – 192.168.36.126

Broadcast : 192.168.36.127

d. 192.168.43.159/27

xxxxxxxx.xxxxxxxx.xxxxxxxx.10011110

Net Address : 192.168.43.128

Host range : 192.168.43.129 – 192.168.43.158

Broadcast : 192.168.43.159